Taking 3 counters and making them one single number?

[Abadox]

I have 3 counters, Digit1 Digit2 and Digit3. I want to combined all 3 digits into one number without adding them together.

For example if Digit1= 3 and Digit2= 1 and Digit3= 6 I would want the number displayed as 316.

I have tried: value( "Digit1" ) and value( "Digit2" ) and value( "Digit3" ) without success.

Appreciate any help, thanks

[GamesterX23]

There are two ways to do this.

First with another counter object.

Always
- set counter to digit1 * 100 + digit2 *10 + digit3

Another way would be using a string.

Always
- set string to Str$("digit1") + Str$ ("digit2") + Str$("digit3")

[Abadox]

When I try to set the string to Str$("digit1") + Str$ ("digit2") + Str$("digit3") it says error "mixed strings and numbers"

first option worked though, thanks

[Popcorn]

You have the expression wrong. Here's the correct one: Str$(value("Digit1")) + Str$(value("Digit2")) + Str$(value( "Digit3" ))

If you're trying to set the value to a counter, you'll need to wrap it inside val() like this: val(str$(value( "Digit1" ))+str$(value( "Digit2" ))+str$(value( "Digit3" )))