Bejeweled clone, check for one more possible turn

[Tiles]

Regarding to this thread, I have a somehow working example ready.

First, again the picture with all possible turns. So that we know what we talk about.



Example to solve this is attached. The example file is not fully working yet though. I lack the corner cases of the board. It can be that the three necessary bricks are at exactly the corners. practically impossible to build a row then. My current code checks for exactly that though, because i haven`t limited it for that cases yet. Have to rethink and tinker around how to avoid that cases ...

Lots of code for this. So my question is still, is there an easier, more elegand method that i miss? Something to improve? I would even be happy with an AGBO solution. Everything working is very welcome

[Tiles]

Okay, this version now takes the corners into account. Means i have what i wanted. But that shouldn`t stop you. As told, i am at searching for the most elegant solution here

EDIT, meh, still problems. I need to have a second look at it. Misses some valid situations now. Seeems that i need to separate my cornercases a bit more ...

[Tiles]

This version should work. It worked at least proper the first time for one quick test ...

EDIT; a final valuetwister was in the way. So i have reuploaded the example. And i have added a example where everything works with an array instead the overlay. Should be faster ...