Turning on/ off Bits

[King_Cool]

I know about adding 1/ 2/ 4/ 8/ 16/ 32 etc to AltValue to turn on Bits, but if i turn on the same bit 2 times in a row ( without reseting the AltValue to 0 ) that system fails
...
How can i turn on/ off a specific Bit of an Alterable Value?

[DavidN]

Use the OR, AND and XOR operators - these act on the binary representation of the number.

If you had "bits" 4, 8 and 32 on, your current number is 44, the binary for which is 101100.

To turn on bit 16 as well, use 44 OR 16:

44 OR 16 = 101100 OR 010000 = 111100 = 60

Turning on existing bits again will not affect the number...

60 OR 16 = 111100 OR 010000 = Still 60

And, er, I can't quite remember how to turn specific bits off using this system while leaving other bits alone. Perhaps someone else can step in!

[King_Cool]

Thank you DavidN
Theese bit operations are really usefull

[gkinfinity]

I haven't done this recently and I've never actually done anything regarding bits in mmf2, but as I recall you just use OR to add bits, AND to subtract bits, and XOR to toggle bits.

____10111111
And 11110001
__= 10110001 1s are only kept at the bit locations that have 1s in both cases (for the top and bottom number)

[LB]

You can use:
ExpressionA AND (NOT ExpressionB)
To turn off the bits in ExpressionA that are on in ExpressionB

[Jacob]

And, er, I can't quite remember how to turn specific bits off using this system while leaving other bits alone. Perhaps someone else can step in!

Use XOR.

60 XOR 16 = 111100 XOR 010000 = 44