How to return integer as 01 rather than 1 in a string?

[assentec]

Hi I have some code that returns an integer to a string and mods it by 12 or 60 for hours and minutes eg 12:10
however when its 1:01 or returns as 1:1. Is there a way to force a pre 0 digit if the number is less than 9? Thanks

[Popcorn]

I would check if the returned value is below 10, and in that case add a "0" before the digit.
If you absolutely have to do it in one event, you could store the values 0 to 60 in a list, and pick the linenumber that equals the returned value. So if it returns 1, it picks line number one which says "01".

[ChrisBurrows]

MuddyMole posted a 1 line expression for this a few days ago.

[MuddyMole]

Right$("0" + str$( value ), 2)

[assentec]

Right$("0" + str$( value ), 2)

Won't that add it to all of them so the time might come up as 012:059 ?

[MuddyMole]

Yeah. You said you already had the code to get hours and minutes separately?

Let's say your single value is the time in total minutes:

Str$(( Time / 60) mod 12) + ":" + Right$("0" + Str$( Time mod 60), 2)

[Alonso]

I made a workaround to this problem by always adding 1000 when modifying the value (so 1 becomes 1001, 12 becomes 1012), then just getting the last two characters of the digit, using right$(string, 2). If there's a better way, I'd like to know (:.

[Phi]

Try Left$("0", 2-Len(Str$(value)))+Str$(value)
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