5 Counters higest number wins?

[warlords]

Hello everyone

I have a question I would like to have some help with!

I have 5 counters with random(20)

How can I know which counter who have the higest number of all 5 counters?

How to prioritize it, so the higest number wins, then second highest number and so on ...

Is it possiple to make such a thing?

Thanks mark

[Konidias]

Easiest solution: Use the Sort X object. It's pretty self explanatory... You set numbers to different values in the sort array, and then you can sort by decreasing... then you can output that info into a string or list or whatever. But of course I'm not sure how platform friendly the Sort X object is.

Harder but more platform friendly solution: You'll need to create either an array or use a list object or something... anything to keep track of all the numbers, and then run fastloops through the list of numbers and re-order them based on any number that is "above" them in the list. So for example if you have the numbers:

5,2,9,8,6

It would start by looking at number 2 and checking if it is greater than number 5. It isn't, so move on to the next number. Then it checks if number 9 is greater than number 2, and then number 5. It is, so move it above 5 and 2. Then it checks 8 to see if it's greater than 2 5 and 9... it is greater than 2 and 5 so move it above those, etc...

This might not be the best solution because my brain is foggy this morning. I'm sure someone else has a more elegant solution but this one would do in a pinch.

[Popcorn]

Not really what you want, but in cases where you only want the highest value of all the counters, you can use this expression:

Max(Max(Max(Max(value( "Counter" ), value( "Counter 2" )), value( "Counter 3" )), value( "Counter 4" )), value( "Counter 5" ))

[Konidias]

It would really be awesome for MMF3 if they just have a math function that could spit this out... like:

sortValdecrease(#,#,#,#,...)
sortValincrease(#,#,#,#,...)

And so you could do like sortValdecrease(5,2,1,4,3)

and it spits back 5,4,3,2,1

I guess as an array or something... so you could access the numbers like: sortVal[0] would be 5.

edit: essentially what Sort X does... but not needing an entirely new extension just to do simple sorting.