Brain stuck on Min/Max dilemma

[Chrille]

I'm trying to figure out how to use the Min & Max functions to make an expression pick the lowest of two values, but never the lower one if it's too low. I can't figure out HOW or even IF it can be done within one expression or if I'll need an extra event.

Here's how the code works, roughly:
* A loop checks for items in a list.
* On each loop, IF an item is found, it should store its index in a counter, but only if it's lower than the current counter value.
* However... If the current counter value is -1, it should always store the index value.

I guess I'll just go with the two events for now, and see if anyone has Min/Max solution

[Simon]

Use the immediate if object:

blah = (min(vara, varb), "<", threshold_value, max(vara, varb), min(vara, varb))

That will do it in one expression. If you want to always pick the threshold_value or higher, just wrap that whole statement (I'll refer to it as statementa) as follows:

blah = max(threshold_value, statementa)

It's fine to do nested statements and calculations like this.

I hope that helps

[Chrille]

I must say I'm confused! Is there an IF object/extension?

[Simon]

Yarp, I wouldn't have suggested it otherwise It is cross platform too.

[Chrille]

Ah, cheers

I couldn't find it earlier, the extension manager server seems to be down.


(and on that topic)
Is there an alternative method to get the manager's featured extensions? I'm working from different locations and just got back home to realise I can't continue my work since I'm missing ZipObject.mfx on this machine. Did try to google it but only found dead links.

[schrodinger]

I use the Immediate IF object too, and I'm quite happy with that
but my extension manager says it's Windows only?

Whithout this (hopefullybuiltininFusion3 ) extension,
coud this work?

Min(Max(-1,val1),Max(-1,val2))

Assuming that "too low" is clearly defined as "-1":

pick the lowest of two values,
but never the lower one if it's too low ---> "<= -1"

[Ziplock]

"* However... If the current counter value is -1, it should always store the index value."

Problem with Min(Max(-1,val1),Max(-1,val2)) is this will return -1 (neither of the numbers) if BOTH are lower than -1.

[schrodinger]

You're right

What should the function output if both values are lower than -1?
The highest of the two, even if it's lower than -1?

Wait.. I've read more carefully the looping explanation.

loopindex=A
counter=B


B <> -1
if A<B ---> A
else ---> B

B=-1 ---> A

Mmmmm.
Can hardly see a way with Min/Max

[Chrille]

I just went with the two events. I try to use as few extensions as possible

Thanks again guys